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shepuryov [24]
3 years ago
5

Off Topic: when you delete a place on Life360, does the other person in your circle get the notification that you have remove it

?yes or no?
Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

don't think so

Step-by-step explanation:

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What are the solutions of the quadratic equation 4x2 - 8x – 12 = 0?
Juliette [100K]

Answer:

see bottom

Step-by-step explanation:

divide through by 4

x2 - 2x - 3 = 0

x2 - 3x + x - 3 = 0

(x2 - 3x) + (x - 3) = 0

x(x - 3) + 1(x - 3) = 0

(x + 1) (x - 3) = 0

x + 1 = 0 and x - 3 = 0

x = -1 and x = 3

5 0
3 years ago
A circle has a radius of 17 mm. An arc length of the circle is 30 mm. What is the area of the sector that is bound by the arc
nikklg [1K]

Answer:

255mm squared

Step-by-step explanation:

it is true i got it wrong and found out the hard way

7 0
3 years ago
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After selling one third of his apple crop, a farmer sold the remainder at the same price per bushel for $600. What is the value
kolezko [41]
300. if you sold a third. then 2/3 would be left. you can then infer each is 300
3 0
3 years ago
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At the parents evening the ratio of mums to dads was 3:2. Out of 500 appointments how many were with mums?
guajiro [1.7K]

Answer:

300

Step-by-step explanation:

Sum the parts of the ratio : 3 + 2 = 5 parts

Divide the number of appointments by 5 to find the value of one part of the ratio, that is

\frac{500}{5} = 100 ← value of 1 part of the ratio

The mums consisted of 3 parts, hence

3 × 100 = 300 ← appointments with mums

3 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the
gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

y=-16x^2+165x+78 ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put \dfrac{dy}{dx}=0.

So,

\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s

Put x = 5.15 in equation (1).

y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m

So, the maximum height reached by the rocket is 503.39 m.

5 0
3 years ago
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