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stepan [7]
3 years ago
8

A trout was swimming 9 feet below the surface of a lake. It dove down 8 more feet to search for food. What is the position of th

e trout now relative to the surface?
(Here’s another one :/ im dumb UwU)
Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer:

-17

Step-by-step explanation:

Think of it like this

-9+-8

Shtirlitz [24]3 years ago
8 0
-17 :) sorry if I’m wrong doe
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If f(x)=3x-2 and g(x)=x^2+1, find f(g(-1)) and g(f(3))
julsineya [31]

Answer:

f(g(-1))=4

g(f(3))=50

Step-by-step explanation:

We know the definition of both functions: f(x)=3x-2, and g(x)=x^2+1

A) In order to evaluate what f(g(-1)) is, let's first investigate what g(-1) is using the definition for this function:

g(x)=x^2+1\\g(-1)=(-1)^2+1\\g(-1)=1+1\\g(-1)=2

Now let's find what f(2) is using f(x) definition: f(x)=3x-2\\f(2)=3(2)-2\\f(2)=6-2\\f(2)=4

B) In order to evaluate what g(f(3)) is, let's first investigate what f(3) is using the definition for this function:

f(x)=3x-2\\f(3)=3(3)-2\\f(3)=9-2\\f(3)=7

Now let's find what g(7) is using the definition for this function:

g(x)=x^2+1\\g(7)=(7)^2+1\\g(7)=49+1\\g(7)=50

4 0
3 years ago
Multiply<br> 3x( 4x – 3x+5)
Daniel [21]

Answer:

The answer is 3x^(2)+15x

7 0
3 years ago
Read 2 more answers
roselia build a cabinet in the shape of a rectangular prism.The cabinet was 30 inches wide, 4 feet tall,and 18 inches deep. What
ivanzaharov [21]
Vol. of a rect. prism is V = L*W*H.

Here, that vol. is V = (2.5 ft)(1.5 ft)(4 ft) = 15 cubic feet (answer)

Note:  volume (not valume).
6 0
3 years ago
What is the square root of -2i?
Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of z=0-2i. First, convert from Cartesian to polar form:

r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2

\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}

z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})

Next, use the formula \displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr] where \displaystyle k=0,1,2,...\:,n-1 to find the square roots:

<u>When k=1</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]

\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)

\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i

<u>When k=0</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)

\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i

Thus, the square roots of -2i are 1-i and -1+i

4 0
2 years ago
Find the value of these limits
kupik [55]

Step-by-step explanation:

Limit as x approaches 5 from the left is 5^2 + 5(5) + 4 = 54

Limit as x approaches 5 from the right is -6(5)+3=-27

4 0
2 years ago
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