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liubo4ka [24]
3 years ago
15

Rewrite this pseudocode so that, instead of indicating whether or not the target was found in the list, the output is the number

of occurrences of the target. For instance, if list were {8, 3, 5, 1, 3, 9, 2, 8, 3, 3} and target were 3, then the output should be 4, since the number 3 occurs four times in the list.
Computers and Technology
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

THE ANSWER IS EASY

Explanation:

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Answer:

a. I think the <u>Aluminum</u> will conduct heat better.

b. I think the <u>Fiberglass</u> will insulate heat better.

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Note: Your answer doesn't have to be right, they just want you to make a prediction about your answer, that means it's alright to guess, also know I didn't guess I am just telling you that you didn't have to ask this question. <3

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Pseudocode and flowchart.

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A compiler is a separate program that converts the entire source program into a machine language before executing it
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Write an if/else statement that compares the variable age with 65, adds 1 to the variable seniorCitizens if age is greater than
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3 years ago
Write a C++ program that computes the area and perimeter of aspecified shape
leonid [27]

<u>C++ program that computes the area and perimeter of a specified shape</u>

#include <iostream>

#include <cmath>

using namespace std;

void rectangle() //Defining function for rectangle

{ int h,w;

cout << "Enter height: ";

//taking input

cin >> h;

cout << "Enter width: ";

cin >> w;

cout << "The perimeter of the rectangle is " <<2*h+ 2*w << " and the area is " <<h*w << endl;  //printing output

}

void triangle()  //Defining function for triangle

{ int s1,s2,s3,h,w;

cout << "Side 1: ";  //Taking input

cin >> s1;

cout << "Side 2: ";

cin >> s2;

cout << "Side 3: ";

cin >> s3;

cout << "Enter the height: ";

cin >> h;

cout << "Enter the base length: ";

cin >> w;

cout << "The perimeter of the triangle is " <<s1+s2+s3 << " and the area is " <<(.5)*w*h << endl; //printing output

}

void circle()//Defining Function for the circle

{

const double p=3.14;

int w;

cout << "Enter the radius: "; //Taking input

cin >> w;

cout << "The perimeter of the circle is " << p*2*w << " and the area is " << p*w*w<< endl;  //printing output

}

int main()  //driver function

{

int s;

cout << "Enter the shape (1 for rectangle,2 for triangle, 3 for circle): ";

//Asking user for the shape

cin >> s;

switch(s)  //checking which shape it chooses

{

case 1:

rectangle();  //If user type 1 ,then calling rectangle function

break;

case 2:

triangle();   //If user type 2 ,then calling triangle function

break;

case 3:

circle();  //If user type 3,then calling circle function

break;

default:

cout <<"Enter valid choice for shape";  //If user type other than 1,2,3

}

return 0;  

}

<u>Output</u>

Enter the shape (1 for rectangle,2 for triangle, 3 for circle): 1

Enter height:2

Enter width: 3

The perimeter of the rectangle is 10 and the area is 6

<u />

4 0
4 years ago
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