Answer:
Check explanation
Explanation:
Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...
], the first stack will drive elements that starts from position 1 as well as to move its' pointer to
.
The Second stack will begin at the
position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be
Answer:
Following are the statement in C++ language :
#include <iomanip> // header file
using namespace std; // namespace
int main() // main method
{
int x1,x2,x3,x4,x5; // variable declaration
cout<<" Enter the 5 sucessive integer:";
cin>>x1>>x2>>x3>>x4>> x5; // taking 5 input from user
cout<<right;
// prints each of its own line and form a right-justified
cout<<setw(5)<< x1 << "\n" << setw(5) << x2 << "\n" <<setw(5) << x3 << "\n" << setw(5) << x4 << "\n" << setw(5) << x5 << "\n";
return(0);
}
Output:
Enter the 5 sucessive integer: 45
23
445
6
8
45
23
445
6
8
Explanation:
Description of program is given below
- Declared a 5 integer value x1,x2,x3,x4,x5 respectively.
- Read the 5 integer value from user by using cin funtion.
- Finally Print these 5 value in its own line and form a right-justified by using setw() function on it
Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output
Answer:
The web browser sends an HTTP request to the IP address, the IP address then sends the content that are displayed by the browser
Explanation:
The process of converting the typed in URL to a displayed page is as follows;
1) The typed in URL is sent to a DNS recursor by the browser
2) The recursor gets the DNS record for the domain from the cache if the record is cached or when the DNS record for the domain is not cached, the recursor makes a requests to the DNS root from which the name of the TLD nameserver is received
3) The TLD nameserver is contacted by the resolver to obtain the authoritative nameserver's IP address
4) With the information, the resolver contacts the authoritative nameserver and obtains the domain's IP address for the domain the resolver contacts
5) The obtained IP address for the URL's domain is then sent to the browser by the resolver
6) An HTTP request is sent by the browser to the IP address and the data received by the browser from that IP address is rendered and seen as the page content.
Answer:
The pressure gauge reading will be;
12 psi
Explanation:
The question relates to relationship of pressure and area
The given parameters for the measurement are;
The weight of the load = 60 lb
The required area of the piston = 5 in.²
Pressure exerted by a force can be defined as follows;

The weight of the load = The force applied by the load
Therefore;

The gauge reading will be 12 psi.