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3 years ago

X^2 + 49= 0. help me plz will name brainlyest if right!

Mathematics

2 answers:

sergeinik [125]3 years ago

7 0

Answer: x = 7 i ,− 7 i

Step-by-step explanation:

12345 [234]3 years ago

6 0

Subtract 49 from both sides
x^2= -49
x= -49 in square root
x=7

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Read 2 more answers

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

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$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

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3 years ago

X^2 + 49= 0. help me plz will name brainlyest if right!​

X^2 + 49= 0. help me plz will name brainlyest if right!