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2 years ago

7

What is the slope of a line perpendicular to the line whose equation is 3x-3y=543x−3y=54. Fully simplify your answer.

1 answer:

yaroslaw [1]2 years ago

7 0

Your answer is 2x/y.

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There's the 2nd part but I've already done that. I just need an answer or help with this.

guapka [62]

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3 years ago

Wayne Webster is a teacher who makes $45,500 per year. His school district must pay FICA tax in the amount of 7.65% of his pay.

rusak2 [61]

7.2% is the answer i got this one right

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3 years ago

A conjecture and the paragraph proof used to prove the conjecture are shown.

kotegsom [21]

1. Linear Pair Postulate
2. MAngle 3
3.Angle 3
4.Angle Congruence Postulate

Hope this helps!
-Soul

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2 years ago

Read 2 more answers

Please help me now I’m a beginner and I so need help please explain how did you get you answer so I understand thanks

Irina-Kira [14]

Answer:y=2.5(x)

Step-by-step explanation:y=2.5(x)

y=2.5(2)= y=5

7 0

2 years ago

Find cotθ, cosθ, and secθ, where θ is the angle shown in the figure.

Darina [25.2K]

Answer:

$\cos( \theta) = \frac{5}{8} \\ {8}^{2} = {5}^{2} + {opp}^{2} \\ {opp}^{2} = 64 - 25 = 39 \\ opp = \sqrt{39} \\ \sin(\theta) = \frac{\sqrt{39}}{8} \\ \tan(\theta) = \frac{ \sqrt{39} }{5} \\ \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{1}{\frac{ \sqrt{39} }{5}} \\ \cot(\theta) = \frac{5}{ \sqrt{39} } \\ \csc( \theta) = \frac{1}{\sin(\theta)} = \frac{1}{\frac{\sqrt{39}}{8}} \\ \csc( \theta) = \frac{8}{ \sqrt{39} } \\ \sec( \theta) = \frac{1}{\cos( \theta) } = \frac{1}{ \frac{5}{8} } \\ \sec( \theta) = \frac{8}{5}$

5 0

2 years ago