Answer:
-20% aka 20% decrease
Step-by-step explanation:
Standard form of the parabola
The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I
The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II
Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4
Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2
From the above calculations:
x = -3/2
y = 4
Function defines relationship between variables. The value of the f[g(x)] when the value of f(x)=6x+11 and g(x)=x²+6 is f[g(x)]= 36x²+47.
<h3>What is a function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
Given to us
f(x) = 6x + 11
g(x) = x² + 6
As we know the two functions, given to us f(x) = 6x + 11, therefore substitute the value of x as g(x) in order to find the value of f[g(x)] ,
![f(x) = 6x + 11\\\\f[g(x)] = 6(x^2 + 6) + 11\\\\f[g(x)] = 6x^2 + 36 + 11\\\\f[g(x)] = 6x^2 + 47](https://tex.z-dn.net/?f=f%28x%29%20%3D%206x%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206%28x%5E2%20%2B%206%29%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2036%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2047)
Hence, the value of the f[g(x)] when the value of f(x)=6x+11 and
g(x)=x²+6 is f[g(x)]= 36x²+47.
Learn more about Function:
brainly.com/question/5245372