<span>3n-8+2(5n+3)=8n+5+4n first I will do the multiplication
3n-8+10n+6=8n+5+4n Now I will simplify
13n -2 = 12n +5 Now I will add 2 to both sides
13n = 12n + 7 then I subtract 12n from both sides
n = 7</span>
More generally, let 
. Then
which proves the limit is 6. So
The equation y = 3(1.12)^x will double after 6 years.
In order to find this, we need to test all of the numbers in the parenthesis to the 6th power and see which comes closest to 2. We know that after 0 years, each equation will simply have the value of the number outside of the parenthesis, so we need the number inside to be 2 in order to get it to double. The following are each number in the parenthesis raised to the 6th power.
1.50^6 = 11.39
1.17^6 = 2.57
1.06^6 = 1.42
1.12^6 = 1.97
Since the one with 1.12^6 is closest to 2, it is the one that nearly doubles after six years.
Answer:
2.5555555555555556
Step-by-step explanation:
-2-7=-9
-23/-9=2.5555555555555556
Answer:
Lines y = -x+4 and y= 3x+3 intersect the y-axis
