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VladimirAG [237]
3 years ago
10

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity re

mains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?
A) +2.93 times 10^5 J
B) 0J
C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.
D) -2.93 times 10^5 J
Physics
1 answer:
olasank [31]3 years ago
3 0

Answer:

The answer is A

Explanation:

Work done = mgh

where mass, m = 92kg, g= 9.81, height,h= 325m

Therefore,

W= mgh

W=92*9.81*325

W=293319

W=2.93*10>5

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