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Alina [70]
3 years ago
10

A bicyclist moves at a constant speed of 4 ms-1 how long will it take for the bicyclists to move 36m?

Physics
1 answer:
Talja [164]3 years ago
3 0
It would take the bicyclist 9 seconds to move 36m.
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Explain how longitudinal waves and transverse waves are similar to each other and different from each other.
VashaNatasha [74]
Similar:
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For transverse waves, the waves move in perpendicular direction to the source of vibration.
For longitudinal waves, the waves move in parallel direction to the source of vibration .
They are similar in the sense that energy is transferred in the form of waves.
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Difference:
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Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.
Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.
3 0
3 years ago
Help m-e-e people -_-!​
xxTIMURxx [149]

Answer:

the answer is

Explanation:For equilibrium

Weight = Tension

mg=T

∴T=4×3.1π=12.4πN (as can be inferred from the question)

Y=

△l/l

T/A

​

=

1000

0.031

​

/20

12.4π/π(

1000

2

​

)

2

​

=

4×0.031

12.4×20×1000×(1000)

2

​

=2×10

12

N/m

2

6 0
3 years ago
Answer all these questions for a TON OF POINTS
IgorC [24]
1). E
2). A
3). 4N
4). D
3 0
3 years ago
Read 2 more answers
A 50 kg student climbs 3 m to the top of a set of stairs.
VashaNatasha [74]
1) PE=mgh
mass 50 kg; height 3; g 9.81
50×3×9.81=1471.5 J

2. The student is opposing gravity force so 
Fgrav=m×g
50 × 9.81= 490N
Work=force×displacement
490×3=1470J(this should always be the same as the potential energy)

3.Power=work×time
4410 W=1470×3

4. Greater than: power is dependent on work, work is dependent on force, force is dependent on weight, 

3 0
3 years ago
A light source simultaneously emits light of two wavelengths, 480 nm and 560 nm, respectively. The source is used in a double-sl
Assoli18 [71]

Answer:

0.48 cm

Explanation:

given data

wavelength = 480 nm

wavelength = 560 nm

slit spacing = 0.040 mm

distance between double slits and the screen  = 1.2 m

solution

we know that  (1 nm= 10^{-9} m)

we wil take here equation of equations of interference that is

ym = R × (m λ)/d    ..........................1

here m = 2 R  i.e distance of screen and slit

 so put here value and we get

separation between the second-order bright fringes = 0.48 cm

6 0
4 years ago
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