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Makovka662 [10]
3 years ago
9

Alejandro has gone to school StartFraction 5 Over 7 EndFraction of the last 35 days. Which expression can be used to determine t

he number of days Alejandro has gone to school? 35 divided by 7 = StartFraction 5 Over 7 EndFraction 35 times StartFraction 5 Over 7 EndFraction StartFraction 5 Over 7 EndFraction divided by 35 StartFraction 7 Over 5 EndFraction divided by 35
Mathematics
2 answers:
TiliK225 [7]3 years ago
8 0

Answer:b

Step-by-step explanation:

I’m not freaking dumbbbb

Arte-miy333 [17]3 years ago
3 0

Answer:

Expression B

Step-by-step explanation:

<em>Let us find the information in the question</em>

  • Alejandro has gon to school \frac{5}{7} of the last 35 days
  • We need to find the expression that represents the number of days Alejandro has gone to school.

<em>We must write the given information in an expression then look for it in the choices.</em>

∵ He has gone \frac{5}{7} of 35 days

→ "of" means times (×)

∴ The days that he has gon = 35 × \frac{5}{7}

<em>The expression that can be used to determine the number of days he has gone to school is</em> 35 × \frac{5}{7}

The choices are:

A) \frac{35}{7}=\frac{5}{7}

B) 35 × \frac{5}{7}

C)  \frac{5}{7} ÷ 35

D) \frac{7}{5} ÷ 35

The answer is B

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A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
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3 years ago
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