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svp [43]
4 years ago
12

Question 4

Mathematics
1 answer:
Kaylis [27]4 years ago
3 0

The car requires 192 ft to stop from a speed of 48 mph

<u>Explanation:</u>

Given:

Speed, u = 30 mph

Stopping distance, d = 75 feet

The stopping distance d of a car after the brakes are applied varies directly as the square of the speed, u

So,

d = k (u)²

On substituting the value:

75 = k (30)²

k = \frac{75}{900} \frac{ft hr^2}{miles^2}

Speed, u₂ = 48 mph

d₂ = ?

d₂ = k (u₂)²

On substituting the values we get:

d₂ = \frac{75}{900} X (48)^2

d₂ = 192 ft

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