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Anna35 [415]
4 years ago
9

bone-shaped treats are five for 3:50 at Shelly store in Sarah wants to buy 12 she set up and solve this proportion to find how m

uch they would cost describe her error and find the correct solution

Mathematics
2 answers:
Travka [436]4 years ago
4 0

Sarah multiplied the denominator by the denominator and the numerator by the numerator instead of finding the cross products. The equation should be 5x = 42, so the cost should be $8.40.

Valentin [98]4 years ago
3 0

Answer:

8.4 dollars

Step-by-step explanation:

The error is in the resolution of the proportion. In fact, the initial proportion is correct:

\frac{5}{3.5}=\frac{12}{x}

where x is the total cost. However, the following step of the resolution is wrong. In fact, the correct resolution is the following:

- Multiplying by x on both sides:

\frac{5x}{3.5}=12

- Multiplying by 3.5 no both sides:

5 x = 12 \cdot 3.5 \\5x = 42

And now we can find x:

x=\frac{42}{5}=8.4

So, the total cost is 8.4 dollars.

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.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo
r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you find their mean height \bar X = 80 cm with standard deviation s = 10.8 cm.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average height of hobbit.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 66 cm      {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, H_A : \mu > 66 cm      {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                     T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

where, \bar X = sample mean height = 80 cm

             s = sample standard deviation = 10.8 cm

             n = sample of hobbits = 7

So, <u><em>test statistics</em></u>  =  \frac{80-66}{\frac{10.8}{\sqrt{7}}}  ~ t_6

                              =  3.429

The value of t test statistics is 3.429.

<em>Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

<em />

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0
4 years ago
The perimeter of a quarter circle is 14.28 KM. What is the quarter circle's radius?
lawyer [7]
Circumference= 2πr
Circumference= perimeter

14.28km= 2(3.14)r
14.28= 6.2831853072r
divide both sides by 6.2831853072
2.27= r

ANSWER: The radius is 2.27km

Hope this helps! :)
3 0
3 years ago
Please help me thanks
BabaBlast [244]

Answer:

16.7

Step-by-step explanation:

We can use the Pythagorean theorem, a^2 + b^2 = c^2.

a = 11

c = 20

11^2 + b^2 = 20^2

121 + b^2 = 400

b^2 = 279

b = sqrt(279) = 16.7

5 0
3 years ago
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
Vesnalui [34]

Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

(c) 0.0401

(d) 0.6464

Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0
3 years ago
Solve for Z 3-4(Z+1)=3Z-(2+Z) Enter you answer as a simple fraction
skelet666 [1.2K]
3 - 4z - 4 = 3z - 2 - z

-4z - 1 = 2z - 2

2z + 4z = -1 + 2

6z = 1

z = 1/6

Hope this helps!
5 0
3 years ago
Read 2 more answers
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