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3 years ago

Solve y = ax2 + c for x

Mathematics

2 answers:

Jet001 [13]3 years ago

5 0

Subtract the c from both sides first. then divide by a2 on both sides and x should equal y-c/a2

Leni [432]3 years ago

4 0

Answer:

B on e2020

Step-by-step explanation:

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What value of x makes the equation true <br> 2 (6x-1) = -38

Anestetic [448]

Answer:

<h3> $\boxed{\bold{\boxed{ \sf{x = - 3}}}}$ </h3>

Step-by-step explanation:

$\sf{2(6x - 1) = - 38}$

Distribute 2 through the parentheses

⇒ $\sf{12x - 2 = - 38}$

Move constant to right hand side and change it's sign

⇒ $\sf{12x = - 38 + 2}$

Calculate

⇒ $\sf{12x = - 36}$

Divide both sides of the equation by 12

⇒ $\sf{ \frac{12x}{12} = \frac{ - 36}{12} }$

Calculate

⇒ $\sf{x = - 3}$

Hope I helped!

Best regards!!

5 0

3 years ago

Find the area of the following triangle. Round your answers to the nearest tenth. a = 44 in, b = 66 in, c = 88 in

swat32

P=44+66+88/2=198/2=99
With Heron formula:
S=root 99*(99-44)(99-66)(99-88)=root 99*55*33*11=root 1976535= 1405.8929.....=1405.9

6 0

3 years ago

Please help will give Brianliest!!!

marshall27 [118]

Answer: y=2(x-3)-5

I hope this is good enough:

8 0

3 years ago

Janey's height from age 7 to 12 can be modeled by the function h(t)=45+8/5t, where h(t) is Janey's height in inches and t is tim

aliina [53]

Write the ratio as a fraction in the fourth column of the table.

6 0

3 years ago

What is the value of x? Round to the nearest tenth. Please Help

Elodia [21]

Answer:

Step-by-step explanation:

The segment 20.2 cm is the tangent. Therefore x and 20.2cm are perpendicular.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=x,\ leg=20.2cm,\ hypotenuse=(14.7+x)cm$

Substitute:

$x^2+20.2^2=(14.7+x)^2$ <em>use (a + b)² = a² + 2ab + b²</em>

$x^2+408.04=14.7^2+(2)(14.7)(x)+x^2$ <em>subtract x² from both sides</em>

$408.04=216.09+29.4x$ <em>subtract 216.09 from both sides</em>

$191.95=29.4x$ <em>divide both sides by 29.4</em>

$x\approx6.5\ cm$

7 0

3 years ago