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Anestetic [448]
3 years ago
14

F leonard bought 2 packs of batteries for x amount of dollars, how many packs of batteries could he purchase for $5.00 at the sa

me rate
Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0
1.
The rate at which Leonard bought was 2 packs per x dollars, 

that is his buying rate was (2 packs)/(x dollars)=2/x (p/$)

2.

with 1 $ Leonard buys 2/x packs
then
with 5 $ Leonard buys (2/x)*5 = 10/x packs.

Answer: 10/x packs
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The sum of 3 times a number and -2, added to 5 times the number
givi [52]

Answer:

3x + (5x -2)

Step-by-step explanation:

X is any number so 3 times a number is 3x. -2 plus 5 times a number is the same as 5 times a number minus 2. And the sum would be 3x + (5x - 2)

3 0
2 years ago
the sum of two numbers is 67. the smaller number is 3 less then the larger number. what are the two numbers?
Shkiper50 [21]
<span>thats the answer

x2 - 8x - 15

hope it helps


</span>
7 0
3 years ago
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The green shape is a dilation Of the black shape. What is the scale factor of the dilation?
Marrrta [24]
Sorry I’m not smart but if I’m not wrong I think it’s 3/15...
4 0
3 years ago
HELPPPP ITS TIMEDDD WILL GIVE BRAINLYISTTTT
Morgarella [4.7K]
I’m pretty positive it’s 4 units. good luck!
8 0
3 years ago
A lumber company is making doors that are 2058.0 millimeters tall. If the doors are too long they must be trimmed, and if the do
USPshnik [31]

Answer:

No, we don't have sufficient evidence to support the claim that the doors are either too long or too short.

Step-by-step explanation:

We are given that a lumber company is making doors that are 2058.0 millimeters tall. If the doors are too long they must be trimmed, and if the doors are too short they cannot be used.

A sample of 11 is made, and it is found that they have a mean of 2043.0 millimeters with a standard deviation of 25.0.

Let \mu = <u><em>population mean length of doors</em></u>.

So, Null Hypothesis, H_0 : \mu = 2058.0 millimeters      {means that the mean length of doors is 2058.0 millimeters}

Alternate Hypothesis, H_A : \mu\neq 2058.0 millimeters     {means that the doors are either too long or too short}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 2043.0 millimeters

             s = sample standard deviation = 25.0 millimeters

             n = sample of doors = 11

So, <u>the test statistics</u> =  \frac{2043.0-2058.0}{\frac{25.0}{\sqrt{11} } }

                                     =  -1.989  

The value of t-test statistics is -1.989.

Now, at a 5% level of significance, the t table gives a critical value between -2.228 and 2.228 at 10 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean length of doors is 2058.0 millimeters.

7 0
2 years ago
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