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Irina18 [472]
4 years ago
10

We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts

, diamonds, spades, and clubs), our deck will be made up of the following.
Each card will have:
i) One rank from 1 to 15.
ii) One of 9 different suits.

Hence, there are 135 cards in the deck with 15 ranks for each of the 9 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards!

The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get.

a) How many different ways are there to get any 5 card hand?
The number of ways of getting any 5 card hand is
Mathematics
1 answer:
Natasha2012 [34]4 years ago
3 0

Answer:

Step-by-step explanation:

There are 5 cards we are selecting out of 135 cards so how many ways can we draw 5 cards at a time (w/o replacement)

There are 135 ways to choose the first card.

There are then 134 ways to choose the second card.

There are then 133 ways to choose the third card.

132 to choose the 4th

131 to choose the 5th.

Now multiply those giving 135*134*133*132*131 or you could have just said

135 P 5.

In case you don't know P means permutation.

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Andreas93 [3]

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7 0
3 years ago
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
Pavel [41]

Answer:

0.818

Step-by-step explanation:

Since the shipment has a ton of aspirin tablets, we can assume that we pick 13 of them <em>with</em> <em>reposition, </em>because the probability shoudn't change dramatically from the probability of picking without reposition if we do so.

We call D the amount of defective tablets. If we assume that we pick the tablets with reposition, then we obtain that D is a random variable of Binomial distribution with parameters 13 and 0.6 (the probability of picking a defective tablet).

We want D to be at most one. To calculate the probability of that event we add up the probability of D being equal to 0 and the probability of D being equal to one. Since D is binomial, we have

  • P(D = 0) = (1-0.06)^{13} = 0.447
  • P(D = 1) = {13 \choose 1} * 0.06^1 * (1-0.06)^{12} = 13*0.06*0.94^{12} = 0.371

We conclude that

P(D \leq 1) = P(D = 0) + P(D = 1) = 0.447+0.371 = 0.818

Hence, the shipment will be accepted with probability 0.818

<em>I hope this helps you!</em>

6 0
3 years ago
In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting
laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

E= z^*\dfrac{\sigma}{\sqrt{n}}

, where n= sample size.

\sigma = Population standard deviation

z*= Critical value(two-tailed).

As per given  , we have

\overline{x}=1438

n= 35

\sigma=269

For 98% confidence  , the significance level = 1-0.98=0.02

By z-table , the critical value (two -tailed) =z^* = z_{\alpha/2}=z_{0.01}=2.326

Now , the maximum error = E= (2.326)\dfrac{269}{\sqrt{35}}

E= (2.326)\dfrac{269}{5.9160797831}

E= (2.326)\times45.4692989044=105.761589252\pprox105.76

Hence, With 98% confidence level , the maximum error = $105.76.

4 0
3 years ago
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