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mars1129 [50]
3 years ago
12

Last​ weekend, a herd of antelope moved to better grazing land. The herd traveled 11nine tenths miles on​ Friday, 17one fifth mi

les on​ Saturday, and 14one fifth miles on Sunday. How far did the herd migrate to the better grazing​ land? If the herd had traveled the total distance in equal​ parts, how far would the herd have moved each​ day?
Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

The herd migrated a total of 43 3/10 miles and migrated about 14 13/30 miles a day.

Step-by-step explanation:

11 9/10 + 17 1/5 + 14 1/5 =

11 9/10 + 17 2/10 + 14 2/10 =

29 1/10 + 14 2/10 =

43 3/10

43 3/10 divided by 3/1 =

433/10 x 1/3 =

433/30 =

14 13/30

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koban [17]
That's 5 integers...

Logic tells me that a number divided by 5 should be equal to -3. -15/5 is in fact equal to -3.

Let's find 5 integers (two positive and three negative) when added up together equal -15.

-14, -3, -3, 2, 3.

[(-14)+(-3)+(-3)+2+3]/5 = (-15)/5 = -3

Mean = -3

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Now let's put these numbers in order, from lowest to highest - then pick out the middle value...

-14, -3, [-3], 2, 3

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Let's look at the numbers once again...

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It turns out that -3 appears the most, therefore -3 is the mode too.
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madam [21]

(If It's a number like this: 8/9 then it's a fraction)

Answer:

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Step-by-step explanation:

Yay, I love doing these!

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Read 2 more answers
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viktelen [127]

9514 1404 393

Answer:

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Step-by-step explanation:

Let 'a' represent the number of adult tickets.

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250 adult tickets were sold.

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<em>Additional comment</em>

I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.

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