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mars1129 [50]
3 years ago
12

Last​ weekend, a herd of antelope moved to better grazing land. The herd traveled 11nine tenths miles on​ Friday, 17one fifth mi

les on​ Saturday, and 14one fifth miles on Sunday. How far did the herd migrate to the better grazing​ land? If the herd had traveled the total distance in equal​ parts, how far would the herd have moved each​ day?
Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

The herd migrated a total of 43 3/10 miles and migrated about 14 13/30 miles a day.

Step-by-step explanation:

11 9/10 + 17 1/5 + 14 1/5 =

11 9/10 + 17 2/10 + 14 2/10 =

29 1/10 + 14 2/10 =

43 3/10

43 3/10 divided by 3/1 =

433/10 x 1/3 =

433/30 =

14 13/30

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Each rug is 1/8 of the floor space. So, 4 rugs would cover half of the floor space. Multiply, then reduce.
4(1/8)=4/8 or 1/2
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2 years ago
Y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP
Nesterboy [21]

Answer:

x intercept (10.5,0)

y intercept (0, -21)

Step-by-step explanation:

y=-2x-21

there are two intercept for a line

x intercept, the point of given equation of  line which lies on x axis.

For x intercept corodinate of y is o

Thus, value x intercept is form (x,0)

putting these value in y=-2x-21, we find x intercept

0=-2x-21

2x = 21

x = 21/2 = 10.5

Thus, x intercept (10.5,0)

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For Y intercept coordinate of x is o

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5 0
3 years ago
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
beks73 [17]
<h2>Answer:</h2>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

<h2>Step-by-step explanation:</h2>

In the question,

Taking the elevation of pool along the y-axis, and length of the board along the x-axis.

On drawing the illustration in the co-ordinate system we get,

lₓ = 2 m

uₓ = 2.5 m/s

and,

h_{y}=9.5\,m

So,

From the equations of the laws of motion we can state that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}

So,

On putting the values we can say that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=(0)t+\frac{1}{2}(9.8)t^{2}\\t^{2}=\frac{9.5}{4.9}\\t^{2}=1.93\\t=1.39\,s

Now,

The <u>equation of the motion in the horizontal</u> can be given by,

v_{x}=u_{x}+a_{x}t\\v_{x}=2.5+a_{x}(1.39)\\So,\\v_{x}=1.39a_{x}+2.5

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

6 0
3 years ago
HELP!!!
irina1246 [14]

Answer:

x=-120

x=-102

Step-by-step explanation:


8 0
3 years ago
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