Question

A box contains four red marbles, six blue marbles, and eight yellow marbles game. Fred chooses one randomly, and replaces it. If he performs this simulation 90 times, how many times should he not draw a blue marble?

Answer 1

Answer:

60 times (?)

Explanation:

So, I doubt my math skills (especially probability) but I hope I did this right!

So, since Fred has:

4 Red

6 Blue

8 Yellow

That leaves us with a grand total of 18 marbles. Now, out of those 18 marbles, we need to find the probability of randomly picking a blue marble.

There are 6 blue marbles out of 18 total marbles, so that leaves us with 6/18

6/18 can easily be simplified to 1/3, so there is a 1/3 chance of randomly picking a blue marble.

1/3 of 90 is 30, so out of 90 times, Fred should statistically pull 30 blue marbles. If you want the amount of him NOT pulling blue marbles, then just subtract 30 from 90, and that leaves us with 60!