#1 is similar to write it out it’s triangle FHG ~ triangle KJL #2 is also but #3 and #4 aren’t
Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
<span>No sé la forma correcta de hacerlo, pero encontrar conjuntos de dos números que pueden igualar 12, luego encontrar cuál de los encaja en la segunda ecuación correctamente.</span>
If its multiplication sipmlest form is, 6/10
If its addition simplest form is, 7/9
If its any other just tell me! Hope i was right :p