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Kobotan [32]
3 years ago
14

What is 20 x 3/4 in simplest form?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
20*3/4 = 60/4....and 60/4 = 15
ElenaW [278]3 years ago
4 0
20 x 3/4 is 15 in simplest form
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Help please, I attached the question. Is it a!? <br> 
AVprozaik [17]

Answer:

A

Step-by-step explanation:

Recall that for a quadratic equation of the form:

0=ax^2+bx+c

The number of solutions it has can be determined using its discriminant:  

\Delta = b^2-4ac

Where:

  • If the discriminant is positive, we have two real solutions.
  • If the discriminant is negative, we have no real solutions.
  • And if the discriminant is zero, we have exactly one solution.

We have the equation:

2x^2+5x-k=0

Thus, <em>a</em> = 2, <em>b</em> = 5, and <em>c</em> = -<em>k</em>.

In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:

b^2-4ac=0

Substitute:

(5)^2-4(2)(-k)=0

Solve for <em>k</em>. Simplify:

25+8k=0

Solve:

\displaystyle k = -\frac{25}{8}

Thus, our answer is indeed A.

3 0
2 years ago
Read 2 more answers
A: 2x + 8y = 5 B: x + 9y = 10
zalisa [80]
Hope this helps you!

3 0
3 years ago
Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.<br><br> 16x0 + 2x2 • y –1
swat32

Given that,

The given expression is : 16x^0+2x^2{\cdot}y^{-1}

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

16x^0+2x^2{\cdot}y^{-1}

Put x = 2 and y = 4 in the above expression.

16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18

So, the value of the above expression is 18.

6 0
2 years ago
A biased coin is tossed 40 times. Out of those 40 tosses, the coin landed on heads 12 times.
Ierofanga [76]

Answer:

Step-by-step explanation:The probability of picking the biased coin: P(biased coin)=1/100. The probability of all three tosses is heads: P(three heads)=1×1+99×18100. The probability of three heads given the biased coin is trivial: P(three heads|biased coin)=1.

7 0
3 years ago
The air force reports that the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a
Anon25 [30]

Answer:

Step-by-step explanation:

<em>Given that X -  the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>

<em />

<em>Height of male pilot = 74.2 inches</em>

<em />

<em>We have to find the percentile</em>

<em />

<em>X = 74.2</em>

<em />

<em>Corresponding Z score = 74.2-72.6 = 1.6</em>

<em />

<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>

<em />

<em>i.e. only 5% are below him in height.</em>

<em />

<em>Thus the malepilot is in 5th percentile.</em>

4 0
2 years ago
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