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GaryK [48]
3 years ago
5

Similarly, the Windows server OS can run regular workstation applications such as MS Office or Adobe Photoshop. Why is this a ba

d idea? Can you find a situation where it might be appropriate?
Computers and Technology
1 answer:
aniked [119]3 years ago
8 0

Answer:

It affects the system speed

Explanation:

The normal windows server OS can run the regular workstation applications like the MS Office or the Adobe Photoshop. Photoshop is an editor that have one of its function as being an editor that helps to edit the picture itself by changing the pixels or edit anything in the image.

On the other hand, Ms Office would help to crop or resize or adjust the brightness etc.

When it comes to cropping or reducing/increasing the brightness of the images then Office is of agreat help as it is free where as for photo shop advanced editing to the images can be done.There is the situation where both needs to be used.

Also running both the application on a egular workstation would make the system slow and also both the applications would not be required at the same time at many times.

You might be interested in
Michael works for a graphic design firm. He is creating an informative poster. He needs to add a great deal of text in the poste
Dennis_Churaev [7]

Michael will use a Adobe Photoshop or CorelDraw   tool to help format the text for creating an informative poster.

<h3>What application is used for graphic design?</h3>

They are:

  • Adobe Photoshop
  • Illustrator, GIMP
  • CorelDraw
  • Canva  and others

Based on the American Institute of Graphic Arts (AIGA), graphic design is known to be a term that is described as “the art and method of planning and bringing forth ideas and experiences along with the use of visual and textual content.”

Therefore, Michael will use a Adobe Photoshop or CorelDraw   tool to help format the text for creating an informative poster.

Learn more about graphic design from

brainly.com/question/27019704

#SPJ1

3 0
2 years ago
Azzam is reviewing a paper he just wrote about kinetic friction for his physics class. On the third page, he realizes that every
bogdanovich [222]

Answer: Azzam used the tool while he was on the third page

Explanation:

The most likely the reason why the phrase was not fixed is because Azzam used the tool while he was on the third page.

This can be infered from the information given when we're told that he uses the Find and Replace tool and clicks on "Replace All" to fix the issue with regards to the error that he made and thus was done from the third page. Therefore, the tool might not have worked for the first page.

4 0
3 years ago
What does it mean for a wireless network to be operating in "infrastructure mode"? If the network is not in infrastructure mode,
Alex_Xolod [135]

Answer and Explanation:

Within the following operating mode, most of the wireless controller remains linked through the main point (access point) for that broader server. The server runs within ad-hoc modes when this does not run under the following mode. Wireless servers wouldn't have the connectivity to interact within ad-hoc mode.

So, the following statement is correct according to the given scenario of the following mode.

4 0
3 years ago
If the object instance is created in a user program, then the object instance can access both the public and private members of
rewona [7]

Answer:

False

Explanation:

The private member of a class is not accessible by using the Dot notation ,however the private member are those which are not accessible inside the class they are accessible outside the class  .The public member are accessible inside the class so they are accessible by using the dot operator .

<u>Following are the example is given below in C++ Language </u>

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {     return 3.14*r*r;  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 3.5;  

 double t= r1.area(); // calling

cout<<" Area is:"<<t;  

   return 0;  

}  

Output:

compile time error is generated

<u>The correct program to access the private member of class is given below </u>

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {    

r1=r;

double t2=3.14*r2*r2;

return(t2); // return the value  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 1.5;  

 double t= r1.area(); // calling

cout<<" Area is:"<<t;  

   return 0;  

}  

Therefore the given statement is False

5 0
3 years ago
Consider the following definition of a recursive method. public static int mystery(int[] list, int first, int last) { if (first
ozzi

Answer:

c. 27

Explanation:

  • In recursion method, a method calls itself until a condition becomes true and returned back. In mystery(), at first time, first is 0 and last is 4. Condition is checked and 0!=4 so else part is executed in which again mystery is called with first as 1 and last 4. This will go again and again until first=4.
  • When first=4 it is also equal to last so if part is executed and alpha[4] is returned which is 9, now it comes alpha[3] +9 which is 8+9 =17 .
  • It is returning values to its previous calls that is why it will reduce to alpha[0]+alpha[1]+alpha[2]+17 which is nothing but sum of all elements of a alpha
  • Then, 1+4+5+8+9=27.
5 0
3 years ago
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