What does "ttyt" stand for?
2 answers:
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Answer:
b. Code an include preprocessor directives for the members
Explanation:
Namespace in programming can be defined as the declarative region which provides scope for the identifiers such as the functions, name of the types, variables, etc.
The namespaces are the code into the logical groups and also used to prevent the name collision.
The ways that can be used outside the namespace as :
-- the code used the fully qualifies name
-- by using the declaration to bring one of the identifier into the scope
-- by using the directive to bring all the things in the newspaper into the scope.
Thus the correct option is (b).
Answer:
The root is:
Explanation:
Use this script in Matlab:
-------------------------------------------------------------------------------------
function [c, err, yc] = bisect (f, a, b, delta)
% f the function introduce as n anonymous function
% - a y b are the initial and the final value respectively
% - delta is the tolerance or error.
% - c is the root
% - yc = f(c)
% - err is the stimated error for c
ya = feval(f, a);
yb = feval(f, b);
if ya*yb > 0, return, end
max1 = 1 + round((log(b-a) - log(delta)) / log(2));
for k = 1:max1
c = (a + b) / 2;
yc = feval(f, c);
if yc == 0
a = c;
b = c;
elseif yb*yc > 0
b = c;
yb = yc;
else
a = c;
ya = yc;
end
if b-a < delta, break, end
end
c = (a + b) / 2;
err = abs(b - a);
yc = feval(f, c);
-------------------------------------------------------------------------------------
Enter the function in matlab like this:
f= @(x) 0.005*(exp(2*x)*cos(x))
You should get this result:
f =
function_handle with value:
@(x)0.005*(exp(2*x)*cos(x))
Now run the code like this:
[c, err, yc] = bisect (f, 1, 2, 1e-10)
You should get this result:
c =
1.5708
err =
5.8208e-11
yc =
-3.0708e-12
In addition, you can use the plot function to verify your results:
fplot(f,[1,2])
grid on
