Answer:
punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']
def strip_punctuation(strWord):
for charPunct in punctuation_chars:
strWord = strWord.replace(charPunct, "")
return strWord
Explanation:
The function is defined with a single argument.
A for loop is ran to check each character of the the word.
If a punction mark is present as a character in the word, it is removed.
The same word is returned but without the punctuation marks.
Assistive technology is commonly used by people with multiple disabilities. It helps them to live more comfortable and it makes their life much easier.
Answer:
Variable Where Declared
In Sub1 :
A Sub1
Y Sub1
Z Sub1
X Main
In Sub2:
A Sub2
B Sub2
Z Sub2
Y Sub1
X Main
In Sub3 :
A Sub3
X Sub3
W Sub3
Y Main
Z Main
Explanation:
In static-scoped languages with nested subprograms, the declaration of a variable is checked with the subprogram, if it is not found, it check within the parent method that called it, it continue until it find a declaration, if no declaration is found, it display an error.
In Sub1, a, y, z is declared there while the declaration of x is found in main.
In Sub2, a, b, z is declared, declaration of y is found in sub1 and declaration of x is found in main.
In Sub3, a, x, w is declared while the declaration of y, z is from the main.
If I'm not mistaken firewalls should be enough as now the automatically back up all data
