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3 years ago

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

Mathematics

1 answer:

Shalnov [3]3 years ago

8 0

Answer:

D. 150 metres

Step-by-step explanation:

speed = (60) times 5/18 = 50/3

lenght of the train = (speed x time)

lenght = 50/3 times (9)

= 150 m.

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It is 42 1/2 miles from Eaton to Baxter and 37 4/5 miles from Baxter to Wellington. How far is it from Eaton to Wellington if yo

mina [271]

All you need to do is add the miles from Eaton to Baxter and from Baxter to Wellington to get your answer...

42 + 37 = 79

Now we need to add the fractions

$\frac{1}{2} + \frac{4}{5} = ...
$

To add we need a common denominator.
2 and 5 can both go into 10, so that will be a our common denominator.
Now you have...
$\frac{5}{10} + \frac{8}{10} = \frac{14}{10}$
which is equal to $1 \frac{2}{5}$
add that to the 79 we got earlier ...

The toal and final answer is $80 \frac{2}{5}$ miles !
Hope I helped and remember to vote this as the brainliest answer ! :)

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3 years ago

Write an expression that represents the product of q and 8, divided by 4.

Sholpan [36]

Answer:

8 q / 4 =2q

Step-by-step explanation

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3 years ago

Math word problem. What's the equation I use?

UkoKoshka [18]

You would have to find the proportionality of the two. If his shadow is 3 feet long, and the tree's shadow is 9 that means it is proportioned by 3. So the height of the tree would be 15.

3 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

If a drink costs 2.32, how many drinks can you buy with 13 dollars?

Llana [10]

Answer:

5 drinks

Step-by-step explanation:

If the drinks cost $2.32 and you have $13 you can divide 13 by 2.32

13/2.32+ 5.6034...

You cannot buy a partal drink so you look at only the whole number which is 5.

6 0

3 years ago

Read 2 more answers