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timurjin [86]
3 years ago
15

Factoring 0=6X^2+x-7

Mathematics
1 answer:
trapecia [35]3 years ago
5 0
The answer is X=-7 and X=6
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Please help me? step by step:) ty
Illusion [34]

Answer:

multiply 5 x 4 = 20

multiply the dimensions of the lighter square

after all the multiplying you subtract your answers and you should get the VERY final answer

*don't add because it's area; just multiply

4 0
3 years ago
Please help!!! For extra credit.
qaws [65]

Answer:

x=24

Step-by-step explanation:

8x-13 = 7x+11; (because it's a rectangle)

8x - 7x = 11 + 13; (moving xs to one side, the rest to the other)

x = 24

7 0
3 years ago
For cheerleading practice, Kiara must be able to lift her legs so that they are parallel to her outstrached arms. For each side
podryga [215]
If this is the dance position you are describing, then the arm and the leg of the dancer both make "right" angles (90º angles) to the floor.
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3 years ago
A parks and recreational board in Birch County is interested in estimating the proportion of its residents in favor of having mo
ankoles [38]

Answer:

B.

Step-by-step explanation:

Trust me.

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5 0
3 years ago
4) Dan Ariely and colleagues have conducted some extremely interesting studies on cheating (see, for example Mazar, Amir, &
lianna [129]

I've attached the complete question.

Answer:

Only participant 1 is not cheating while the rest are cheating.

Because only participant 1 has a z-score that falls within the 95% confidence interval.

Step-by-step explanation:

We are given;

Mean; μ = 3.3

Standard deviation; s = 1

Participant 1: X = 4

Participant 2: X = 6

Participant 3: X = 7

Participant 4: X = 0

Z - score for participant 1:

z = (x - μ)/s

z = (4 - 3.3)/1

z = 0.7

Z-score for participant 2;

z = (6 - 3.3)/1

z = 2.7

Z-score for participant 3;

z = (7 - 3.3)/1

z = 3.7

Z-score for participant 4;

z = (0 - 3.3)/1

z = -3.3

Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96

Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.

Thus, only participant 1 is not cheating while the rest are cheating.

8 0
3 years ago
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