All categories

3 years ago

A sports club is planning a cookout. The food

Mathematics

1 answer:

DIA [1.3K]3 years ago

3 0

Answer:

maximum number: 171

Step-by-step explanation:

The $500 budget that will serve the people (x) with flat fee of $200 and $1.75 per person

1.75x + 200 = 500

1.75 x = 300

x = 171.4

You might be interested in

Is -30 - (-52) positive or negative?

Luba_88 [7]

Answer:

positive

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1. What is the factored form of q2 - 12q + 36? (1 point)

Novay_Z [31]

Step-by-step explanation:

${q}^{2} - 12q + 36 \\ = {q}^{2} - 6q - 6q + 36 \\ = q(q - 6) - 6(q - 6) \\ \huge \red{ \boxed {= (q - 6)(q - 6) }}\\ is \: the \: factored \: form.$

3 0

3 years ago

Lucy made $323 for 17 hours of work.

saveliy_v [14]

19 minutes I think just divide 323 and 17

3 0

3 years ago

6.Angle 30degrees + x is equal to 180 degrees. Find x

Harrizon [31]

The answer is 150 because 30+150=180

6 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago