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Kobotan [32]
3 years ago
8

A sports club is planning a cookout. The food

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

maximum number: 171

Step-by-step explanation:

The $500 budget that will serve the people (x) with flat fee of $200 and $1.75 per person

1.75x + 200 = 500

1.75 x = 300

x =  171.4

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What is the sum of the last four terms of the series 7+9+11+...21
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For sake of convenience, reverse the series, then it would be:

21,19,17.....7

a=21, d = -2,

s(4) = 4/2 (21+15)

s(4)=2(36)

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4 years ago
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svetlana [45]

Answer:

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Anna11 [10]

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3 0
2 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
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