How do you figure out 3/2 divide 1/4=N. What is n between

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Anuta_ua [19.1K]

Answer:

a) c = 1/15

b) =2/5

c) = 3/5

d) No, it cannot be the PMF of y.

Step-by-step explanation:

We have that

$p_X(x)\geq0$

4 0

3 years ago

Helppppppppppppppppppppp!!!!!!!!!1

vitfil [10]

Answer: I need help too

Step-by-step explanation:

I think is -6

6 0

3 years ago

15h - m = 13h + q pleas helppp

tensa zangetsu [6.8K]

I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2

Explanation:

15h-m=13h+q
-13h -13h
———————-
2h-m=q
+m +m
———————-
2h=q+m
/2 /2 /2
———————-
H=q/2+m/2

8 0

3 years ago

Read 2 more answers

The distance from Fort Worth to Fresno is 1,530 miles. If a cyclist maintains an average speed of 17 miles per hour, how many ho

Tju [1.3M]

The time take for the cyclist to travel from Fort Worth to Fresno is $90 \ hours$

Explanation:

It is given that the distance from Fort Worth to Fresno is 1,530 miles.

The average speed of the cyclist is 17 miles per hour.

The time travelled by the cyclist can be determined using the formula,

$Distance=Speed \times Time$

Substituting the value of distance and speed, we get,

$1530=17\times Time$

Dividing both sides by 17, we get,

$90 =Time$

Thus, the time take for the cyclist to travel from Fort Worth to Fresno is $90 \ hours$

3 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago