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just olya [345]
3 years ago
12

When (3,-2) is reflected across the x-axis the resulting image point is:

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

(3,2)

Step-by-step explanation:

when reflecting across the x axis the y value becomes - while the x value stays the same

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Answer:

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Step-by-step explanation:

On the original segment (black endpoints), the (red) point is the most accurate to being 2/3 the distance from endpoint (-3,8)

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For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
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\end{array}\\\\
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\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
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\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Point e is located at -5,2 point m is the reflection of point e what is the distance between e and m
nataly862011 [7]

Answer:

the distance is 10

Step-by-step explanation:

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and the refection of -5,2 is 5,2

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4 0
3 years ago
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