(a) 6 hours and 45 minutes
(b) 2 hours and 35 minutes
(c) 2 hours and 40 minutes
(d) 3 hours and 20 minutes
Answer:
147.67 and 142.50
Step-by-step explanation:
Cents are only two digits after the decimal, aka hundredths. So, you have to round each number to the hundredth.
The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>
let
x-------> total <span>weight of candies
we know that
x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
20x-15x=30
5x=30
x=6 lb
the answer is
6 lb
Are you sure you've copied down the original problem exactly as given? i38 = 38i can't be simplified. Perhaps you meant i^38, which is a different matter.
Note that i^38 = i^32 * I^4 * I^2.
Note that i^0, i^4, i^8, etc., all equal 1. Therefore,
i^38 = (1)(1)i^2 = 1*(-1) = -1 (answer)
Part A: To find the lengths of sides 1, 2, and 3, we need to add them together. We can do this by combining like terms (terms that have the same variables, or no variables).
(3y² + 2y − 6) + (3y − 7 + 4y²) + (−8 + 5y² + 4y)
We can now group them.
(3y² + 4y² + 5y²) + (2y + 3y + 4y) + (-6 - 7 - 8)
Now we simplify
12y² + 9y - 21
Part B: To find the length of the 4th side, we need to subtract the combined length of the 3 sides we know from the total length (perimeter).
(4y³ + 18y² + 16y − 26) - (12y² + 9y - 21)
Simplify, subtract like terms.
4y³ + (18y² - 12y²) + (16y - 9y) + (-26 + 21)
4y³ + 6y² + 7y - 5 is the length of the 4th side.
Part C (sorry for the bad explanation): A set of numbers is closed, or has closure, under a given operation if the result of the operation on any two numbers in the set is also in the set.
For example, the set of real numbers is closed under addition, because adding any two real numbers results in another real number. Likewise, the real numbers are closed under subtraction, multiplication and division (by a nonzero real number), because performing these operations on two real numbers always yields another real number.
<em>Polynomials are closed under the same operations as integers. </em>
