Let the length of the north and south sides be x, then the length of the east and west side is 32/x.
The total fencing needed is the perimeter of the rectangle = 2x + 2(32/x) = 2x + 64/x
Cost of fencing the north and south sides is 2(2x) = 4x
Cost of fencing the east and west sides is 4(64/x) = 256/x
Total cost (C(x)) of fencing the vegetable patch is 4x + 256/x
For minimum cost dC/dx = 0
4 - 256/x^2 = 0
4x^2 - 256 = 0
x^2 = 64
x = 8
Therefore, the <span>dimensions of the vegetable patch with the least expensive fence is
</span><span>north and south sides = 8 ft
</span><span>east and west sides = 32/8 = 4 ft</span>
Answer:
$120
Step-by-step explanation:
80%=$96
1%=80%/80=96/80=1.2
100%=1%×100%=1.2×100=120
9514 1404 393
Answer:
(x, y) = (4, 5)
Step-by-step explanation:
Equating the expressions for y gives ...
-1/4x +6 = x +1
5 = 5/4x . . . . . . . add 1/4x-1
4 = x . . . . . . . . . . multiply by 4/5
y = x +1 = 4 +1
y = 5
The solution is (x, y) = (4, 5).
If the circulation for newspaper 1 is 382 thousand more than the circulation for newspaper 2 and their combined is 2502 thousand find the circulation for each paper
Answer: Let x be the circulation for newspaper 2.
Then the circulation for newspaper 1 is
thousand
We are given the combined circulation of newspaper 1 and newspaper 2 is 2502 thousand





Therefore, the circulation of newspaper 2 is 1060 thousand and circulation of newspaper 1 is 1060 + 382 = 1442 thousand