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vazorg [7]
3 years ago
9

Which of the following are mass communication methods? (Select all that apply.)

Computers and Technology
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

Blogs, radio news, and social media

Explanation:

All of these outlets can reach thousands if not millions of people. The only means of communication that cannot reach masses of people is hand-written letters, as they can only be read by one person at a time and have to be physically sent by person to person.

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What is the statement describing? Agile team continuously adapt to new circumstances and enhance the methods of value delivery
Vera_Pavlovna [14]

Answer:

Continuous Integration

Explanation:

In continuous integration process, A program or piece of code is edited, tested and validated by team of software developers or contributors to complete and deploy the single project. This practice will improve the quality and reliability of the code.

Improvement, delivery and deployment are the three different phases, to complete the process of continuous integration.The individuals who contribute in a code or program  in terms of improvement, delivery and deployment make a team that leads to continuous integration.

So, Agile team Continuously adapt Continuous Integration to new circumstances and enhance the methods of value delivery.

8 0
3 years ago
g Write a function called price_of_rocks. It has no parameters. In a while loop, get a rock type and a weight from the user. Kee
Scilla [17]

Answer:

<u>The pseudocode:</u>

FUNCTION price_of_rocks():

  SET total = 0

  while True:

      INPUT rock_type

      INPUT weight

      if rock_type is "Quartz crystals":

         SET total += weight * 23

      elif rock_type is "Garnets":

         SET total += weight * 160

      elif rock_type is "Meteorite":

         SET total += weight * 15.50

       

       INPUT choice

       if choice is "n":

           break

 

   RETURN total

END FUNCTION

<u>The code:</u>

def price_of_rocks():

   total = 0

   while True:

       rock_type = input("Enter rock type: ")

       weight = float(input("Enter weight: "))

       

       if rock_type == "Quartz crystals":

           total += weight * 23

       elif rock_type == "Garnets":

           total += weight * 160

       elif rock_type == "Meteorite":

           total += weight * 15.50

           

       choice = input("Continue? (y/n) ")

       if choice == "n":

           break

   

   return total

print(price_of_rocks())

Explanation:

Create a function named price_of_rocks that does not take any parameters

Initialize the total as 0

Create an indefinite while loop. Inside the loop:

Ask the user to enter the rock_type and weight

Check the rock_type. If it is "Quartz crystals", multiply weight by 23 and add it to the total (cumulative sum). If it is "Garnets", multiply weight by 160 and add it to the total (cumulative sum). If it is "Meteorite", multiply weight by 15.50 and add it to the total (cumulative sum).

Then, ask the user to continue or not. If s/he enters "n", stop the loop.

At the end of function return the total

In the main, call the price_of_rocks and print

4 0
3 years ago
Fill in the blanks, so the print statement displays the result of the function call in order.
sergejj [24]

Answer:

Rep;ace the blank with

smaller, bigger

So, the complete line is:

smaller,bigger=order_numbers(100,99)

Explanation:

From the question, we understand that the program is to return the order of a number from least to highest

This has been well implemented in order_numbers function

Because the order function returns two values, the order_function must be called in order to accept two values and the syntax is:

<em>value1,value2 = function(return-value1,return-value2)</em>

In this case, the statement is:

smaller,bigger=order_numbers(100,99)

So, in the next line of the main, the values of smaller and bigger are printed:

<em>print(smaller,bigger)</em>

See attachment

Download txt
8 0
3 years ago
Given the following function definition
siniylev [52]

Answer:

B. 1 6 3

Explanation:

Given function definition for calc:

void calc (int a, int& b)

{

int c;

c = a + 2;

a = a * 3;

b = c + a;

}

Function invocation:

x = 1;

y = 2;

z = 3;

calc(x, y);

cout << x << " " << y << " " << z << endl;

  • Since x is passed by value, its value remains 1.
  • y is passed by reference to the function calc(x,y);

Tracing the function execution:

c=3

a=3

b=c+a = 6;

But b actually corresponds to y. So y=6 after function call.

  • Since z is not involved in function call, its value remain 3.

So output: 1 6 3

3 0
3 years ago
ANYONE WANNA FRIEND ME ON DISCORD ゴRose joestarゴ#2088
Sergeeva-Olga [200]

JOJO fan!?!!?!??!?!?!!?!?

6 0
3 years ago
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