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PilotLPTM [1.2K]
4 years ago
10

Is a plotter input output or both

Computers and Technology
1 answer:
erastova [34]4 years ago
5 0

Answer:

it is output

Explanation:

it just is .

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You have inserted new slides based on a Word outline. How do you format these new slides to match the PowerPoint presentation fo
snow_lady [41]

It would be either A or D. Either way, you would get your pptx to look good.

If you need any questions about Access Database, ask me, I took a college class on Access Database, and I am an expert at it.

Thank you!

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4 years ago
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Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For exam
ryzh [129]

Answer:

Explanation:

The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.

import java.util.*;

class Test

{

   public static void main(String[] args)

   {

       String X = "photograph";

       String Y = "tomography";

       System.out.println(X + '\n' + Y);

       System.out.println("Longest common substring length: " + longestSub(X, Y));

   }

   static int longestSub(String X, String Y)

   {

       char[] word1 = X.toCharArray();

       char[] word2 = Y.toCharArray();

       

       int length1 = X.length();

       int length2 = Y.length();

       int substringArray[][] = new int[length1 + 1][length2 + 1];

       int longestSubstringLength = 0;

       

       for (int i = 0; i <= length1; i++)

       {

           for (int j = 0; j <= length2; j++)

           {

               if (i == 0 || j == 0)

                   substringArray[i][j] = 0;

               else if (word1[i - 1] == word2[j - 1])

               {

                   substringArray[i][j]

                           = substringArray[i - 1][j - 1] + 1;

                   longestSubstringLength = Integer.max(longestSubstringLength,

                           substringArray[i][j]);

               }

               else

                   substringArray[i][j] = 0;

           }

       }

       return longestSubstringLength;

   }

}

8 0
3 years ago
Plz answer me will mark as brainliest ​
andrezito [222]

1. entertainment

2. windows media player

6 0
3 years ago
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Modify the statistics program from this chapter so that client programshave more flexibility in computing the mean and/ or stand
vampirchik [111]

Answer and Explanation:

Using Javascript:

function mean(nums){

var array_numbers= new array(nums);

var meanofNums= array_numbers.reduce()/array_numbers.length;

Console.log(meanofNums);

}

Function Std(nums){

var OurArray= new Array(nums);

var meanOfnums= mean(nums);

var i;

for(i=0; i<=OurArray.length; i++){

OurArray[i]= OurArray[i]-meanOfnums*OurArray[i]-meanOfnums;

}

var al_stdOfnums= OurArray.reduce()/OurArray.length;

var stdOfnums= Math. sqrt(al_stdOfnums);

Console.log(stdOfnums);

}

function meanStdDev (nums){

mean(nums);

Std(nums);

}

/*From the code above, we have defined functions and used them in the last function definition meanStdDev (nums), making for code reusability. In defining the functions, we have followed the formulas for calculating mean and standard deviations and implemented in that order. Notice how we used a for loop in std(nums) function definition to iterate through the elements of the array nums, squaring each value and reassigning a new value for each element(using index value) in the array. We then added these values in array using reduce method, dividing by array length and square rooting the value using the math object method sqrt().*/

8 0
3 years ago
Last semester, Henri bought his textbooks over the Internet and saved a considerable amount of money. Classes start in a few day
castortr0y [4]

Answer:

limited problem solving

Explanation:

Henri will probably use a limited problem-solving process, we reach this conclusion due to two factors:

  1. The time he has to take the decision is short, therefore he can calmly evaluate his options
  2. His past positive experience in buying books online will influence his decision

I hope you find this information useful and interesting! Good luck!

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3 years ago
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