the answer to the problem is 2y^3 3x3y4+4
Initially there were 12 dogs
dogs left at the end of day =4
number of dogs sold=12-4=8
price of one dog=$104
price of 8 dogs = 104*8= $832
initially there were 8 cats
cats left at the end of day =5
number of cats sold =8-5=3
price of one cat= $25
price of 3 cats =25*3= $75
ratio of sales for dogs to cats = 832/75
Answer:
x=0, y=2. (0, 2).
Step-by-step explanation:
3x+2y=4
8x-3y=-6
---------------
3(3x+2y)=3(4)
2(8x-3y)=2(-6)
-----------------------
9x+6y=12
16x-6y=-12
----------------
25x=0
x=0/25
x=0
3(0)+2y=4
0+2y=4
2y=4-0
2y=4
y=4/2
y=2
We can distribute
2(5)+2(-x)=10-2x
we get
8+10-2x=?
18-2x=?
whatever that ? is, we don't know
multiply both sides by -1
2x-18=-?
add 18 to both sides
2x=18-?
divide bth sides by 2
x=9-(?/2)
whatever the left side it, just divide it by 2 and subtract it from 9
