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Brums [2.3K]
3 years ago
8

There are 4 students in a small class. To make a team, the names of 2 of them will be drawn from a hat. How many different teams

of 2nstudents are possible?
Mathematics
2 answers:
inessss [21]3 years ago
6 0

Answer:

3

Step-by-step explanation:

2*2 - 1 = 3

never [62]3 years ago
3 0

Answer:

3

Step-by-step explanation:

List all the different teams:

A+B, C+D

A+C, B+D

A+D, B+C

There are 3.

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Which relation is a function?
I am Lyosha [343]

B. Because it makes a linear line.

7 0
3 years ago
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A model of a building is 18 inches tall. If the building is really 678 feet tall, how tall is a window that is 1/9 in on the mod
ipn [44]

Answer:

50.2in or 4.2ft

Step-by-step explanation:

This is a problem about proportions so I generally set up my problems like below. I just set some variable here to make it easier to refer back to the measurements for each. You don't have to do this, I am just showing it for clarity. I will convert everything to inches too. We need to find the real window height.

Mb = model building = 18in

Mw= model window = \frac{1}{9}in

Rb = real building = 678ft = 8136in

Rw = real window = ?

\frac{Mw}{Mb} = \frac{Rw}{Rb}

\frac{1/9}{18} = \frac{Rw}{8136}

\frac{1}{9*18} = \frac{Rw}{8136}  

\frac{1}{162} = \frac{Rw}{8136}

\frac{1*8136}{162}= \frac{8136*Rw}{8136}

\frac{8136}{162} = Rw

\frac{452}{9} = Rw

Rw ≈ 50.2in ≈ 4.2ft

5 0
2 years ago
20. (06.07 )
Scrat [10]
20 is the best answer
4 0
3 years ago
Write a simplified polynomial expression in standard form to represent the area of the rectangle below.
olga nikolaevna [1]

(2x-4)(x+5)  expand with indicated multiplication

2x^2+10x-4x-20

2x^2+6x-20

3 0
3 years ago
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
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