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3 years ago

What are the zeroes of f(x) = x2 − 6x + 8? (4 points) x = −4, 2 x = −4, −2 x = 4, 2 x = 4, −2

Mathematics

2 answers:

babymother [125]3 years ago

8 0

Hey there! :)

Answer:

Third option. x = 2, and x = 4.

Step-by-step explanation:

Find the zeros of this quadratic equation by factoring:

f(x) = x² - 6x + 8

Becomes:

f(x) = (x - 4)(x - 2)

Set each factor equal to 0 to solve for the roots;

x - 4 = 0

x = 4

x - 2 = 0

x = 2

Therefore, the zeros of this equation are at x = 2, and x = 4.

Elena L [17]3 years ago

7 0

Answer:

x=4 x=2

Step-by-step explanation:

f(x) = x^2 − 6x + 8

To find the zeros, set equal to zero

0 = x^2 − 6x + 8

Factor

What 2 numbers multiply to 8 and add to -6

-4*-2 = 8

-4+-2 = -6

0 = ( x-4) (x-2)

Using the zero product property

x-4 =0 x-2=0

x=4 x=2

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Explanation:

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Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

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Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

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Using all the information we have, we can find the explicit rule:

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We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

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$a_{1} = 32 • 1$

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$a_{6} = 1$

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