If u man just simplifying it
B^8+c^10 (just add exponents)
Answer:
First triangle
Step-by-step explanation:
First triangle is the obtuse triangle.
We notice that the upper trapezoid is symmetric to the lower one & the line of symmetry should be a horizontal line (mirror line) where any point of the upper vertices should be at equal distance (perpendicular) with the related vertices of the lower one from this horizontal line:
Note that QQ" =4 units, Hence the line of symmetry is the perpendicular to QQ' at 2 units
You are correct in thinking that the columns of the first matrix must match with the rows of the second matrix.
So for example, we can multiply a 1 x 5 matrix with a 5 x 7 matrix. The two matching '5's are directly what make multiplication possible in this case. For your problem, the first two '3's match and multiplication is possible.
The rows of the first matrix don't need to match with the columns of the second matrix.
<span>3) This one is a little different, since you're finding the angle instead of the side. You can denote the angle to be the variable x. Thus:
cos x = 14 / 26
Use a calculator to divide out 14/26, then round to four decimals.
cos x = 0.5385
Now go to the cosine chart and find which angle has the cosine 0.5385. It's a strange problem they gave you, because the chart doesn't have a value that matches it (kind of confusing if you ask me). But you can find two angles it is between. Notice that cos 57° = 0.5446 and cos 58° = 0.5299. Thus, the angle must be between those two. It turns out it is closer to 57°, so you can say:
x = 57° </span>
