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3 years ago

Consider the matrix show below:

Mathematics

1 answer:

Zinaida [17]3 years ago

6 0

Answer:

The Answer is B

Step-by-step explanation:

Put the equation into desmos.com/matrix

it is a 2 row, 2 column matrix, hit Enter

Next line, press the letter A, then press the A^t button and it will give you the answer.

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The midpoint of AB is (-4,-7) if the coordinates of A are (-7,-6) what are the coordinates of B

slava [35]

Answer:

(-1,-8)

Step-by-step explanation:

7 0

3 years ago

Can someone help me find x and y using the 30-60-90 theorem

Fittoniya [83]

X is radical 3
y is 2 radical 3

6 0

3 years ago

Which of the following is a factor of 2x^4 22x^3 60x^2? 2x^3 x^4 x 4 x 5

zavuch27 [327]

The factor theorem says that for a function f(x), if f(a) = 0, then (x - a) is a factor of f(x).
For f(x) = 2x^4 + 22x^3 + 60x^2
f(-5) = 2(-5)^4 + 22(-5)^3 + 60(-5)^2 = 2(625) + 22(-125) + 60(25) = 1250 - 2750 + 1500 = 0
Therefore, x - (-5) = x + 5 is a factor of f(x).

8 0

3 years ago

A teacher reviews 4-1/2 papers per hour, how many papers will that teacher review in 6-1/3 hours

MrRa [10]

Answer:

$28\frac{1}{2}\ papers$

Step-by-step explanation:

step 1

Convert mixed numbers to an improper fractions

$4\frac{1}{2}=\frac{4*2+1}{2}=\frac{9}{2}$

$6\frac{1}{3}=\frac{6*3+1}{3}=\frac{19}{3}$

step 2

we know that

A teacher reviews 9/2 papers per hour

using proportion

Find how many papers will the teacher review in 19/3 hours

Let

x-----> the number of papers

$(9/2)/1=x/(19/3)$

$x=(19/3)(9/2)$

$x=28.5\ papers$

Convert to mixed numbers

$28.5=28\frac{1}{2}\ papers$

5 0

3 years ago

There are 20 small tropical fish swimming in a 55-gallon aquarium. What is the population density?

umka21 [38]

Answer:

The population density is 0.364 fish per gallon.

Step-by-step explanation:

The population density can be defined as the number of individuals (in this case, small tropical fish) per unit of area or volume. In this case, the volume of the aquarium (55 gallon).

The density can be calculated then as:

$d=\dfrac{P}{V}=\dfrac{20\;\text{fish}}{55\;\text{gal}}\approx0.364\dfrac{\text{fish}}{\text{gal}}$

The population density is 0.364 fish per gallon.

5 0

3 years ago