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lukranit [14]
4 years ago
8

Without solving the systems, explain why the following systems must have the same solution.

Mathematics
1 answer:
8_murik_8 [283]4 years ago
6 0

Answer:

Both system of equations are intersecting

Step-by-step explanation:

The equations are of the form

ax+by+c=0

Two equations have no solution when

\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}

i) 4x−5y-13=0

3x+6y-11=0

\frac{4}{3}\neq \frac{5}{6}\neq \frac{13}{11}

So, they are intersecting lines and do have the same solution.

ii) 8x−10y-26=0

x−11y-2=0

\frac{8}{1}\neq \frac{-10}{-11}\neq \frac{13}{11}

So, they are intersecting lines and do have the same solution.

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