The slope of each line segment of ΔQRS are-
- QR = 3/10
- RS = - 10/3
- QS = -7/13
<h3>What is meant by the slope of the line?</h3>
- A slope of a line is defined in mathematics as the change in y coordinate to regard to the shift in x coordinate.
- The net change in y-coordinate is denoted by Δy, whereas the net change in x-coordinate is denoted by Δx.
For the given question,
The coordinates of each vertices of the triangle are-
Q = (-7, -2)
R = (3, 1)
S = (6, -9)
The formula for the slope of the line segment.
Slope = m = (y2 - y1)/(x2 - x1)
Slope QR = (1 + 2)/(3 + 7)
Slope QR = 3/10
Slope RS = (-9 - 1)/(6 - 3)
Slope RS = - 10/3
Slope QS = (-9 + 2)/(6 + 7)
Slope QS = -7/13
Thus, the slope of the each line segment of the given triangle QRS is found.
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14= 4 pi/6 pi = 2/3
15 = 8 pi/10 pi = 4/5
16 = no
Answer:
Not sure what you're asking but 120.4 is
one hundred
two tens
and four tenths
Answer:
A = 121 pi in^2
Step-by-step explanation:
The circumference is given by
C = 2 * pi*r
22 pi = 2 * pi *r
Divide each side by 2 pi
22 pi / (2 pi) = 2 pi r / (2pi)
11 = r
Now find the area
A = pi r^2
A = pi (11)^2
A = 121 pi in^2