First find the area of the parallelogram

Area of parallelogram = b x h
= 12 x 7
= 84

Then find area of kite

Area of kite = (xy)/2
= (7 x 12)/2
= 84/2
= 42

Now we are gonna subtract the area of the kite from the area of the parallelogram.

84 - 42 = 42

Therefore the area of the shaded region is 42.

7 0

3 years ago

Add the polynomials (-12x^5-7x^3+12x^2+11)+(4x^3+6x^2-6x+3)

tatuchka [14]

Answer:

-12x^5-3x^3+18x^2+14

6 0

3 years ago

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with

AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = $\left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]$

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0

3 years ago

I forgot how to do this, can someone help me-

Artyom0805 [142]

Step-by-step explanation:

1) x/20 = -9

By cross multiplication,

x = -180

2) -168 = -14k

k = -168/-14

k = 12

3) -5m = -50

m = 10

4) -320 = -20n

n = 16

5) -4 = x - 5

x = 1

6) -6(-8 + n) = -54

42 - 6n = -54

-6n = -54 -52

6n = 106

n = 17.6

7) 3(x - 9) = -3

3x - 27 = -3

3x = 24

x = 8

8) 9k + 3 = -78

9k = -81

k = -9

9)4 + (n/4) = 8

By taking LCM,

16 + n/4 = 8

16 + n = 32

n = 16

10) -5r + 7 = -73

-5r = -80

r = 16

Hope it helps.

6 0

2 years ago