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Paraphin [41]
2 years ago
8

Help Please this is Study Island sorry for camera quality its asking what is the length of the red segment line. The numbers are

-2 -1 0 1 2 3

Mathematics
1 answer:
Maksim231197 [3]2 years ago
3 0
Your answer is 5.1. hope this helps.
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How do I go about solving this?
Stels [109]
Hello,

Here i am using vectors

\vec{AB}=\vec{DC}=3\vec{i}+3\vec{j}
==> AB//DC and AD//BC (definition of a translation)


The quadrilater ABCD is a parallelogram:
so
1) his diagonals have the same length;

2) his diagonals are cutting in the middle.

(these are proprieties of a parallelogram)
4 0
3 years ago
What is the percentage 45cm of 2m
EleoNora [17]
22.5% is the correct answer. 45/200 = 225.
3 0
3 years ago
0.175 as a percentage
Paul [167]

Answer: 17.5%

To convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 0.175 × 100 = 17.5% (answer).

➥ The ease way:

1) Move the decimal point two places to the right: 0.175 → 1.75 → 17.5.

2) Add a % sign: 17.5%

Answer: 17.5%

3 0
2 years ago
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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
66.6 reoccurring as a fraction .
Setler [38]

Answer:

66 2/3 as a mixed number or 200/3 as an improper fraction.

Step-by-step explanation:

That would be 66 2/3.

0.6 recurring is 2/3.

8 0
3 years ago
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