A.
(7^2)^x = 1
(49)^x = 1
thus x = 0
B.
<span>(7^0)^x=1
(1)^x = 1
thus x can be any real number.
</span>
X² + 11x - 26 = 0
x² - 25 = 0
(x + 13)(x - 2) = 0
(x + 5)(x - 5) = 0
x = -13
x = 2
x = -5
x = 5
Answer:
D (7a-3)/4
Step-by-step explanation:
7a – 4b = 3
Subtract 7a from each side
7a-7a – 4b = 3-7a
-4b = 3 -7a
Divide by -4
-4b/-4 = (3-7a)/-4
b = (7a-3)/4
Answer:
Step-by-step explanation:
Where's the problem/question?
C is correct. You have to pay attention to the corresponding sequences of the vertices. C is correct because in the three triangles, MON, MPO, OPN are the right angles, respectively. However, the angles are not consistent in other given choices.
