<img src="https://tex.z-dn.net/?f=3%20%5Cfrac%7B3%7D%7B4%7D%20%20%5Ctimes%20%5Cfrac%7B2%7D%7B5%7D%20" id="TexFormula1" title="3

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3 years ago

\frac{3}{4} \times \frac{2}{5} " alt="3 \frac{3}{4} \times \frac{2}{5} " align="absmiddle" class="latex-formula">
help meee

Mathematics

1 answer:

Gwar [14]3 years ago

8 0

Answer:

1 1/2

Step-by-step explanation:

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Find x (the answer is a decimal) Picture posted below.

Anettt [7]

Answer:

x = 37.5

hope that helps

5 0

3 years ago

For the equation 2(4x+10)=8x+k, which value of K will create an equation with infinitely many solutions?

saw5 [17]

Answer:

For given linear equation having infinite many solution the value of k is 20 .

Step-by-step explanation:

Given as :

The equation is 2 (4 x + 10) = 8 x + k

For infinite many solution , if the variable cancel out to zero then it will have infinite many solutions

<u>So, from given linear equation</u>

i.e 2 (4 x + 10) = 8 x + k

Or, 2 × 4 x + 2 × 10 = 8 x + k

Or, 8 x + 2 × 10 = 8 x + k

Or, 8 x + 20 = 8 x + k

Or, k + (8 x - 8 x) = 20

Or, k + 0 = 20

∴ k = 20

So, The vale of k = 20

Hence, For given linear equation having infinite many solution the value of k is 20 . Answer

3 0

3 years ago

PLEASE HELP ME If 0 < z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6

Burka [1]

Answer:

z = 6

Step-by-step explanation:

We know that ...

sin(x) = cos(90 -x)

Substituting (9z-1) for x, this is ...

sin(9z -1) = cos(90 -(9z -1))

But we also are given ...

sin(9z -1) = cos(6z +1)

Equating the arguments of the cosine function, we have ...

90 -(9z -1) = 6z +1

90 = 15z . . . . . . . . . add (9z-1) to both sides

6 = z . . . . . . . . . . . . divide by 15

_____

<em>Comment on the graph</em>

The attached graph shows 5 solutions in the domain of interest. These come from the fact that the relation we used is actually ...

sin(x) = cos(90 +360k -x) . . . . . for any integer k

Then the above equation becomes ...

90 +360k = 15z

6 +24k = z . . . . . . . . . for any integer k

The sine and cosine functions also enjoy the relation ...

sin(x) = cos(x -90)

sin(9z -1) = cos(9z -1 -90) = cos(6z +1)

3z = 92 . . . . . equating arguments of cos( ) and adding 91-6z

z = 30 2/3

6 0

3 years ago

Verify sin^4 x - sin^2 x = cos^4 x - cos^2 x is an identity

Citrus2011 [14]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

sin(x)^4 - sin(x)^2 = cos(x)^4 - cos(x)^2

sin(x)^2 = 1 - cos(x)^2:

sin(x)^4 - 1 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

-(1 - cos(x)^2) = cos(x)^2 - 1:

cos(x)^2 - 1 + sin(x)^4 = ^?cos(x)^4 - cos(x)^2

sin(x)^4 = (sin(x)^2)^2 = (1 - cos(x)^2)^2:

-1 + cos(x)^2 + (1 - cos(x)^2)^2 = ^?cos(x)^4 - cos(x)^2

(1 - cos(x)^2)^2 = 1 - 2 cos(x)^2 + cos(x)^4:

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = ^?cos(x)^4 - cos(x)^2

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = cos(x)^4 - cos(x)^2:

cos(x)^4 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0

3 years ago

I need help on 14 and 15.

Savatey [412]

Answer:

14 one 15 6

Step-by-step explanation:

6 0

3 years ago