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DiKsa [7]
3 years ago
12

Bought computer for $500. Marked down $50. Plus a 25% discount off original price. What is the original price?

Mathematics
2 answers:
andriy [413]3 years ago
8 0
So 500+50=550

550=25-100=75%

550=75%
multiply both sdies yb 4
2200=300%
divide by 3
733.333=100%

the origonal price=$733.33
vodomira [7]3 years ago
3 0
500 + 50 = 550
500 is 25% of what number?
2000 + 550 = 2550 dollars

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Allushta [10]
If it takes 10 machines 10 minutes to make 10 items, I would assume it would take 50 machines 50 minutes to make 50 items. Hope this helps :)
5 0
3 years ago
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Scientists want to know the total trout population in a part of Lake Michigan. They tagged and released 200 trouts back into the
blondinia [14]
The estimate would be 1200.

We will set up a proportion for this.  10 out of 60 of the sample were tagged, so that is the first ratio.  The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top).  We do not know the total number so we use a variable:

10/60 = x/200

Cross multiply:

10*x = 60*200
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6 0
3 years ago
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qaws [65]
You would multiply the like (or similar) terms together. 

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8 0
3 years ago
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Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

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Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
A^2+b^2+c^4=2020. Yes
pychu [463]

Answer:

yes

Step-by-step explanation:

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3 years ago
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