First option. The inequality can be split into two separate inequalities.
The answer should be 664 in squared
Answer:(X+Y)²
X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.
X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.
(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:
X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².
Answer:
Option C.
Step-by-step explanation:
The top box must ALWAYS contain the answer to the problem.
Answer:17/2pi
Explained:
Just writing longer so I don’t have to go into details. If this is on khan academy you don’t have to show your work!
