Answer:
Length: 10 units.
Width:6 units
Step-by-step explanation:
Part a has 1 unit =40 yards. When we have 1 unit = 20 yards, we have divided the original numbers, 40, in half, getting 20. That means that we need to double the original amount of units, like you see above.
Answer:
Mean: 23. 54545455
Median: 22
Step-by-step explanation:
The median represents the center the most because when you are solving for the median, you look for the direct center of the terms which will be 22, the median.
Answer:
x=-6/7^7-2
Step-by-step explanation:
Answer:
1) The discount is $4.05
The sale price is $18.45
2) The discount is $10
The sale price is $30
3) The discount is $2.6
The sale price is $23.4
Step-by-step explanation:
1) What is the discount and sale price for a haircut that originally cost $22.50 with an 18% discount.
Actual Price= $22.50
Discount = 18%
Finding discount:

So, the discount is $4.05
Finding Sale Price
The sale price can be found by: 
Putting values and finding sale price:

The sale price is $18.45
2) What is the discount and sale price for a sweatshirt that originally priced $40.00 with an 25% discount.
Actual Price= $40.00
Discount = 25%
Finding discount:

So, the discount is $10
Finding Sale Price
The sale price can be found by: 
Putting values and finding sale price:

The sale price is $30
2) What is the discount and sale price for a large pizza that originally cost $26.00 with an 10% discount.
Actual Price= $26.00
Discount = 10%
Finding discount:

So, the discount is $2.6
Finding Sale Price
The sale price can be found by: 
Putting values and finding sale price:

The sale price is $23.4
We have to solve this equation:

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

Now we can find the roots of the quadratic polynomial as:
![\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%5B%5D%7B%28-6%29%5E2-4%5Ccdot1%5Ccdot6%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B36-24%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B12%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B4%5Ccdot3%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm2%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20x%3D3%5Cpm%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_1%3D3-%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_2%3D3%2B%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3