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leonid [27]
3 years ago
10

Geoff planted dahlias in his garden. Daliahs have bulbs that divide and reproduce underground. In the first year, Geoff's garden

produced 6 bulbs. In the second year, it produced 12 bulbs, and in the third year, it produced 24 bulbs. If this pattern continues, how many bulbs should Geoff expect in the eighth year?
A)48 bulbs
B)384 bulbs
C)768 bulbs
D)1,536
I think it's B?
Mathematics
2 answers:
pantera1 [17]3 years ago
6 0
The answer is C because your times each number by 2 6 times 2 is 12, 12 times 2 is 24, 24 times 2 is 48 and you do it 8 times until you get your answer which is 768 bulbs
olchik [2.2K]3 years ago
6 0
This is a geometric sequence of the form:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number

The common ratio, r, is the defining characteristic of geometric sequences.  It is the value found when dividing each term by the previous term.  In this case:

r=24/12=12/6=2 and we see that the initial value is 6 so

a(n)=6(2)^(n-1) so in the eighth year:

a(8)=6(2^7)

a(8)=768

So after eight years there will be 768 bulbs.
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Find the length of AC
aleksandr82 [10.1K]

B)

here,

A to B = 62

C To B = 11

A to C = ?

now,

so, 62 - 11 = 51

therefore a to C Is 51 cm

plz mark me brainliest ok

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A)

Here,

A to B = 13

A to C = 26

total = ?

now,

A to B + A to C

13 + 26 = 39

Therefore,

total number is 39

4 0
2 years ago
What is the approximate area of a circle with diameter 6?
BaLLatris [955]

Answer: 28.27

Step-by-step explanation:

First, you can turn the diameter into a radius, giving you 3. Since the equation of an area in a circle is A=πr^2, you must square 3, giving you 9. Now you must multiply 9 with Pi, which is 3.14159265358, but just 3.14 for short. With that, you get about 28.27 as area.

7 0
2 years ago
Joe has a collection of 35 DVD movies. He received 8 of them as gifts. Joe bought the rest of his movies over 3 years. If bought
Degger [83]
He buys 9 dvds for 3 years
7 0
3 years ago
Read 2 more answers
Don’t mind the blue tete
jeka94
Your answer is gonna be C.
5 0
3 years ago
How to solve log base 5 of x + log base 5 of (4x-1)
pochemuha
Log5(x)+log5(4x-1)
As the bases are the same the number doesn't matter
Log (a) + log(b) =log (ab)

Log(4x^2-x)

(x )(4x-1)

x=0.25 or x=0

Log(4×0.25^2-0.25) = log(0) = Infinity
Same with 0. So no answer
7 0
3 years ago
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