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lbvjy [14]
4 years ago
15

What is the new coordinate for point S' when the figure is reflected over the line y=x HINT: (just switch the x and y coordinate

s of the points)

Mathematics
1 answer:
Olin [163]4 years ago
7 0

Answer: (1, -2)

Step-by-step explanation:

The original coordinate of S is (-2, 1)

As mentioned, also in the hint, exchange the position of x and y coordinate to get the new coordinate that is reflected after y=x

(basically in the 4th quadrant)

The new coordinate of S' is (1, -2)

Hope this helps!! :)

Please let me know if you have any question

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1/3k+80=1/2k+120 k=??
Sati [7]

Answer:

The value of k is 240

Step-by-step explanation:

\frac{1}{3}k + 80 = \frac{1}{2}k + 120

Or, 120 - 80 =  \frac{k}{2} - \frac{k}{3}

Or, 40 = \frac{k}{6}

So. k = 40 × 6  = 240

Hence The value of k is 240   Answer

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For which values of x is the expression x4 – 10x2 less than -9?
Julli [10]
x^4-10x^2\ \textless \ -9\\
x^4-10x^2+9\ \textless \ 0\\
x^4-x^2-9x^2+9\ \textless \ 0\\
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4 0
3 years ago
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borishaifa [10]
Sin125, on the unit circle, should be positive(not negative), since it should be in quadrant two if the angle 125 degrees is in standard position.
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Factor <br> 50t^2-20t-30=??
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The answer is 10(t-1) (5t+3).

An algebraic equation of the second degree in x is a quadratic equation. Typically, a quadratic equation is expressed in standard form as,ax^2 + bx + c = 0.

And the factor is a number or algebraic expression that divides another number evenly without leaving any remainder.

To factor the given quadratic equation, first, take the common factor of the equation. Therefore,

50t^2-20t-30=10(5t^2-2t-3)

Using the sum-product pattern, we can write 2t as 3t-5t. Therefore,

50t^2-20t-30=10(5t^2+3t-5t-3)

Now, find the common factor between the pairs within the bracket. We get,

50t^2-20t-30=10(t(5t+3)-1(5t+3))

Finally, rewriting the above terms by factoring out the greatest common factor, we get,

50t^2-20t-30=10(t-1)(5t+3)

To know more about factoring quadratic equations:

brainly.com/question/1863222

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