What is the difference between the highest and the lowest medal counts.

Mathematics

2 answers:

liubo4ka [24]3 years ago

5 0

The highest has 28 medals and the lowest has 4 medals, from observation they have 24 medal difference.

drek231 [11]3 years ago

4 0

Answer:

by observation we get to know

highest is 28

lowest is 4

hence difference = 28 - 4 = 24

brainliest plsss

You might be interested in

What is the equation of this line in standard form?

Fiesta28 [93]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{\frac{1}{2}}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{\frac{1}{2}}-\underset{x_1}{(-3)}}}\implies \cfrac{2+1}{\frac{1}{2}+3}\implies \cfrac{3}{\frac{1+6}{2}}\implies \cfrac{\frac{3}{1}}{~~\frac{7}{2}~~}\implies \cfrac{3}{1}\cdot \cfrac{2}{7}\implies \cfrac{6}{7}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{6}{7}}[x-\stackrel{x_1}{(-3)}]\implies y+1=\cfrac{6}{7}(x+3) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{7}}{7(y+1)=7\left( \cfrac{6}{7}(x+3) \right)}\implies 7y+7=6(x+3)\implies 7y+7=6x+18 \\\\\\ 7y=6x+11\implies -6x+7y=11\implies 6x-7y=-11$

3 0

3 years ago

Pls i need this asap

Goryan [66]

Answer:

It would have to be (C) 50.27 because 25 is too short for a diameter of 8 seeing it would be 8x4 to get 32 in which 25 is not long enough for. So the answer is C.

6 0

3 years ago

What inference can we make about 528 students at fridgemont high?

Mama L [17]

Umm yea idk honestly

7 0

3 years ago

Read 2 more answers

Need help asap 10 points, provide explanation please.

hram777 [196]

Answer:

Step-by-step explanation:

Use the distance formula between points to find all sides:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

AB= $\sqrt{13}$

BC= $\sqrt{13}$

CA= $\sqrt{26}$

This is a 45° 45° 90° triangle, where two of the sides are equal and the other side is the first two sides times $\sqrt{2}$ , so yes, it is a right triangle.