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sveta [45]
2 years ago
6

For what value of x do the expression 2x + 3 and 3x - 6 have the same value?

Mathematics
2 answers:
amm18122 years ago
3 0
The value of x is 9, in this expression
Leni [432]2 years ago
3 0

Answer:

the value of x is 9

Step-by-step explanation:

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Extend the sequence and then complete the
andrew-mc [135]

Answer:

l

Step-by-step explanation:

A sequence is an ordered list of numbers.....

A term is an element in a sequence.

You can expand a sequence by finding and writing....

The next term in the sequence is A = (general term)

8 0
3 years ago
A client has orders to receive 2 liters of IV fluid over a 24-hour period with ½ this amount to be infused in the first 10 hours
Tcecarenko [31]

Answer:100 ml/hr

Step-by-step explanation:

client has orders to receive 2 liters of IV fluid over a 24-hour period

½ this amount to be infused in the first 10 hours of treatment = ½ ×2 lires

= 1 litre =1× 000 ml= 1000ml

If 1000 ml is received in 10hrs

x ml will be received in 1 hrs

x = 1× 1000/10

= 100ml per hr

4 0
2 years ago
Simplify 1-5/4(6t-3/4)+3(17-5/17)
Firlakuza [10]
-15t/2 + 14159/272

I'm not exactly sure what you are looking for, but this is what I got.
8 0
3 years ago
PLS HELP!! WILL GIVE BRAINLIEST
Wittaler [7]

Answer:

tbh i do not know the ancer i wish you good luck

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%283x%20%2B%204%29%20%20-%207%20log_%7B4%7D%7Bx%7D%5E%7B2%7D%20%20%2B%20%20log_%
olga2289 [7]

First of all, we need all logarithms to have the same base. So, we use the formula

\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}

To change the second term as follows:

\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}

Finally, using the property

\log(a^b)=b\log(a)

we have

\dfrac{\log_2(x^2)}{2}=\log_2(x)

So, the equation becomes

\log_2(3x+4)-7\log_2(x)+\log_2(x)=2 \iff \log_2(3x+4)-6\log_2(x)=2

We can now use the formula

\log(a)-\log(b)=\log\left(\dfrac{a}{b}\right)

to write the equation as

\log_2(3x+4)-6\log_2(x)=2 \iff \log_2(3x+4)-\log_2(x^6)=2 \iff \log_2\left(\dfrac{3x+4}{x^6}\right)=2

Now consider both sides as exponents of 2:

\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

5 0
3 years ago
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