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Tasya [4]
3 years ago
7

If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

Exp\ 1:3m-4n\\Exp\ 2: n^2-m

The values are:

m=5\\n=-2

Putting the values in expression 1:

3m-4n\\=3(5)-4(-2)\\=15+8\\=23

Putting the values of m and n in second expression

n^2-m\\=(-2)^2-5\\=4-5\\=-1

Multiplying both expressions:

(3m-4n)(n^2-m)=23* (-1)=-23

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

  • brainly.com/question/4142886
  • brainly.com/question/4934417

#LearnwithBrainly

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Five kids can be given cookies in (10 + 5 - 1) C (5 - 1) = 14 C 4 = 1,001 ways.
5 0
3 years ago
3х + 9 = 2х + 5<br><br> is it no solutions, all real numbers, or does x equal something?
zepelin [54]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u>4</u></em></h2>

Step-by-step explanation:

<h3><u>Given</u><u> </u><u>Equation</u><u>:</u></h3>
  • 3x + 9 = 2x + 5

<h3><u>Question</u><u>:</u></h3>
  • Whether x has one solution or infinite solutions or no solutions?

<h3><u>Solution</u><u>:</u></h3>

=> 3x + 9 = 2x + 5

  • <em>(</em><em>On</em><em> </em><em>shifting</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>we</em><em> </em><em>get</em><em>)</em>

=> 3x - 2x = 5 - 9

  • <em>(</em><em>On</em><em> </em><em>subtracting</em><em>)</em>

=> x = - 4

<h3><u>Result</u><u>:</u></h3>

<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>has</u></em><em><u> </u></em><em><u>only</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>solution</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>is</u></em><em><u>,</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u>4</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

7 0
2 years ago
Find the value of the expression:2a(b−c)+b(2c−2a)+4c(0.5a−0.5b)
Agata [3.3K]

Answer:

0

Step-by-step explanation:

2a(b−c)+b(2c−2a)+4c(0.5a−0.5b)

To simplify this we need to remove the parenthesis

Distribute 2a, b and 4c inside the parenthesis

2ab -2ac + 2bc - 2ab + 2ac - 2bc

now we combine like terms'

2ab - 2ab becomes 0

-2ac +2ac becomes 0

+2bc - 2bc becomes 0

So final answer is 0



5 0
3 years ago
divide the numbers 1 to 8 by 9. observe the decimal and discuss your observation of non terminating recurring decimal
Alexeev081 [22]

Answer:

When dividing the numbers 1-8 by 9, we get whatever number was divided as a decimal in repeating form. For example, 2/9 = 0.22222...

<em>Brainliest, please! I'm almost an Ace!</em>

Step-by-step explanation:

1/9 = 0.11111...

2/9 = 0.22222...

3/9 = 0.33333...

4/9 = 0.44444...

5/9 = 0.55555...

6/9 = 0.66666...

7/9 = 0.77777...

8/9 = 0.88888...

5 0
2 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
8090 [49]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by  

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec


6 0
3 years ago
Read 2 more answers
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