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3 years ago

Use the law of cosines to find the length of a

Mathematics

1 answer:

borishaifa [10]3 years ago

4 0

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

$\frac{sin55}{175}=\frac{sin42}{a}$ and solving for a:

$a=\frac{175sin42}{sin55}$ so

a = 143.0

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Answer:

the right answer is A

-x^2-3

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3 years ago

Question is in the image

Lubov Fominskaja [6]

The answer is A, The intersection point is (-5,3) and the equation of the graphs are y = x + 8 and x + y = -2

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3 years ago

Aircraft landing gears coming from a facility are inspected for defects with the aim to improve the failure rates. Historical da

erica [24]

Answer:

78% probability it contains no defects

Step-by-step explanation:

We have that:

10% have defects in shafts only.

8% have defects in bushings only.

4% have the two types of defects.

An assembly is selected arandom, what is the probability it contains no defects

Either it has at least one defect, or it has no defects. The sum of these probabilities is 100%. So

D + ND = 100

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22 + ND = 100

ND = 78

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3 years ago

Use substitution to solve the system of linear equations. In your final answer, include all of your work.

Fantom [35]

Replace 'y' with -3x+4

$x + \frac{1}{3} (-3x+4) = \frac{4}{3} \\ \\ x -x + \frac{4}{3} = \frac{4}{3} \\ \\ \frac{4}{3} = \frac{4}{3}$

The variable 'x' cancels out, leaving the True statement 4/3 = 4/3
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4 0

3 years ago

A population of beetles are growing according to a linear growth model. The initial population (week 0) is p0=6 and the populati

wel

Answer:

P(n)= p0 + 11(n)

Where p0= population of week 0

P(n) = population of n weeks

n= number of weeks

Step-by-step explanation:

Population of beetles in Week 0= 6

Population of beetles in Week 7= 83

From week 0 to week 7 there are 8 weeks.

But subtracting population of week 0 from population of week 7 gives

= 83-6

= 77

After the subtraction, we have 7 weeks remaining.

Dividing the remaining population by the number of weeks remaining

=77/7

= 11

For n number of weeks, population p of beetles

P(n)= p0 + 11(n)

Where p0= population of week 0

P(n) = population of n weeks

n= number of weeks

3 0

3 years ago