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GenaCL600 [577]
4 years ago
5

What is the distance between (4, 7)(4,7)left parenthesis, 4, comma, 7, right parenthesis and (2, 2)(2,2)left parenthesis, 2, com

ma, 2, right parenthesis? Choose 1 answer: Choose 1 answer: (Choice A) A \sqrt{10} 10 ​ square root of, 10, end square root (Choice B) B \sqrt{29} 29 ​ square root of, 29, end square root (Choice C) C 888 (Choice D) D 99
Mathematics
1 answer:
tester [92]4 years ago
7 0

Answer: square root of 29

Step-by-step explanation:

Given the question :

Distance between (4, 7) and (2, 2)

Distance between two points is given by:

Distance = sqrt[(X2 - X1)² + (Y2 - Y1)²]

X1 = 4 ; Y1 = 7 ; X2 = 2 ; Y2 = 2

Distance = sqrt[(2 - 4)² + (2 - 7)²]

Distance = sqrt[(-2² + - 5²)]

= sqrt(4 + 25)

= sqrt(29)

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Step-by-step explanation:

Calculate, rewrite, remove the paretheses

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3 years ago
Please help!
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Answer:

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4 years ago
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3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

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4 0
3 years ago
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Graphing Questions:
Lilit [14]

Answer:

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